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NEET 2000 (AIPMT) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2000 (AIPMT)

Q93NEET 2000 · AIPMTMedium

Heat Engines, Refrigerators & Second Law

The (W/Q) of a Carnot engine is 1/6, now the temperature of sink is reduced by 62oC, then this ratio becomes twice, therefore the initial temperature of the sink and source are respectively

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Answer: (b)

  1. WQ=η=1−T2T1\frac{W}{Q} = \eta = 1 - \frac{T_2}{T_1}: T2=56T1T_2 = \frac{5}{6}T_1 and T2−62=23T1T_2 - 62 = \frac{2}{3}T_1.
  2. Subtract: T16=62⇒T1=372 K=99∘C\frac{T_1}{6} = 62 \Rightarrow T_1 = 372\text{ K} = 99^\circ\text{C}.
  3. T2=310 K=37∘CT_2 = 310\text{ K} = 37^\circ\text{C}
  4. So the answer is (b) 37∘C, 99∘C37^\circ\text{C},\ 99^\circ\text{C}.
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