The water drop falls at regular intervals from a tap 5 m above the… | NEET 1995 (AIPMT)

Q61NEET 1995 · AIPMTEasy

Motion Under Gravity

The water drop falls at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at instant the first drop touches the ground. How far above the ground is the second drop at that instant?

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Answer: (a)

Time for a drop to fall 5 m: $T = \sqrt{2 \times 5/10} = 1$ s
When drop 1 lands, drop 3 is just leaving, so two intervals fit in 1 s: interval $= 0.5$ s.
Drop 2 has fallen for $0.5$ s: $s = \frac{1}{2} \times 10 \times 0.5^2 = 1.25$ m
Height above ground $= 5 - 1.25 = 3.75$ m. So the answer is (a) 3.75 m.

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Motion Under Gravity question from NEET 1995 (AIPMT)

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