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MHT CET 2021 (21 Sep, Shift 2) · Other / Mixed: Atoms & Bohr Links

Other / Mixed: Atoms & Bohr Links question from MHT CET 2021 (21 Sep, Shift 2)

Q4MHT CET 2021 · 21 SEP · SHIFT 2Medium

Other / Mixed: Atoms & Bohr Links

The wave number of the last line of the Balmer series in the hydrogen spectrum will be $($ Rydberg's cons $\text{tant}, R = \frac{10^{7}}{\text{m}})$

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Answer: (d)

Last (series limit) line of Balmer: $n_1 = 2$ , $n_2 = \infty$ .
$\bar{\nu} = R\left(\frac{1}{2^2} - 0\right) = \frac{R}{4}$
$\bar{\nu} = \frac{10^7}{4} = 2.5 \times 10^{6} = 25 \times 10^{5}\text{ m}^{-1}$
So the answer is (d).

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