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MHT CET 2022 (11 Aug, Shift 2) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from MHT CET 2022 (11 Aug, Shift 2)

Q38MHT CET 2022 · 11 AUG · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series

The wave number of the last line of the Balmer series in hydrogen spectrum will be (Rydberg's constant $= 10^{7}\text{ m}^{-1}$ )

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Answer: (b)

Last line of Balmer is the series limit: $\bar{\nu} = R\left(\frac{1}{4} - 0\right) = \frac{R}{4}$ .
$\bar{\nu} = \frac{10^{7}}{4} = 2.5 \times 10^{6}\text{ m}^{-1}$ .
So the answer is (b) $2.5 \times 10^{6}\text{ m}^{-1}$ .

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