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Matter Waves: de Broglie Wavelength question from NEET 2013

Q140NEET 2013Medium

Matter Waves: de Broglie Wavelength

The wavelength $\lambda$ e of an electron and $\lambda$ p of a photon of same energy E are related by

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Answer: (c)

Electron: $\lambda_e = \dfrac{h}{\sqrt{2mE}} \Rightarrow E = \dfrac{h^2}{2m\lambda_e^2}$ .
Photon: $\lambda_p = \dfrac{hc}{E} = \dfrac{2mc}{h}\lambda_e^2$
So $\lambda_p \propto \lambda_e^2$ : the answer is (c).

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