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NEET 1991 (AIPMT) · Photons: Energy, Momentum & Radiation Pressure

Photons: Energy, Momentum & Radiation Pressure question from NEET 1991 (AIPMT)

Q46NEET 1991 · AIPMTEasy

Photons: Energy, Momentum & Radiation Pressure

The wavelength of a 1 keV photon is 1.24×10−91.24 \times 10^{-9} m. What is the frequency of 1 MeV photon?

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Answer: (b)

  1. For the 1 keV photon: ν1=cλ=3×1081.24×10−9=2.42×1017 Hz\nu_1 = \frac{c}{\lambda} = \frac{3 \times 10^{8}}{1.24 \times 10^{-9}} = 2.42 \times 10^{17}\text{ Hz}.
  2. E=hν⇒ν∝EE = h\nu \Rightarrow \nu \propto E; 1 MeV is 1000 times 1 keV.
  3. ν2=1000×2.42×1017≈2.4×1020 Hz\nu_2 = 1000 \times 2.42 \times 10^{17} \approx 2.4 \times 10^{20}\text{ Hz}
  4. So the answer is (b).
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