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JEE Main 2021 (25 Feb, Shift 2) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2021 (25 Feb, Shift 2)

Q44JEE Main 2021 · 25 FEB · SHIFT 2Easy

Transitions, Photon Emission & Excitation

The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n = 2 to n = 1 state is:

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Answer: (d)

$\frac{1}{\lambda} = R\left(1-\frac14\right) = \frac{3R}{4}$ , with $R = 1.097\times10^{7}\ \text{m}^{-1}$
$\lambda = \frac{4}{3\times1.097\times10^{7}}\ \text{m} \approx 1.22\times10^{-7}$ m
$\lambda \approx 122$ nm
So the answer is (d) $121.8$ nm.

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