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JEE Main 2023 (6 Apr, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2023 (6 Apr, Shift 2)

Q52JEE Main 2023 · 6 APR · SHIFT 2Easy

Acceleration Due to Gravity

The weight of a body on the surface of the earth is $100\text{ N}$ . The gravitational force on it when taken at a height, from the surface of earth, equal to one-fourth the radius of the earth is:

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Answer: (b)

$W_h = \frac{W}{(1 + h/R)^2}$ with $h = \frac{R}{4}$ .
$W_h = \frac{100}{(5/4)^2} = 100 \times \frac{16}{25}$
$W_h = 64\ \text{N}$
So the answer is (b) 64 N.

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