The weight of man in a stationary lift is w₁ and when it is moving downwards with uniform acceleration ' a ' is w₂. If the ratio w₁: w₂ = 4: 3, then the value of ' a ' is ( g = acceleration due to gravity) (a) g/3 (b) g/4 (c) 3/4 g (d) 4/g

Answer: (b). w₁ = mg, w₂ = m(g - a). (w₁)/(w₂) = (g)/(g - a) = 4/3 ⇒ 3g = 4g - 4a a = g/4, so the answer is (b).

The weight of man in a stationary lift is w₁ and when it is moving… | MHT CET 2025 (23 Apr, Shift 1)

Q2MHT CET 2025 · 23 APR · SHIFT 1Easy

Apparent Weight & Lift

The weight of man in a stationary lift is $w_1$ and when it is moving downwards with uniform acceleration ' a ' is $w_2$ . If the ratio $w_1 : w_2 = 4 : 3$ , then the value of ' a ' is ( $g =$ acceleration due to gravity)

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Answer: (b)

$w_1 = mg$ , $w_2 = m(g - a)$ .
$\frac{w_1}{w_2} = \frac{g}{g - a} = \frac{4}{3} \Rightarrow 3g = 4g - 4a$
$a = \frac{g}{4}$ , so the answer is (b).

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