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JEE Main 2024 (4 Apr, Shift 2) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from JEE Main 2024 (4 Apr, Shift 2)

Q38JEE Main 2024 · 4 APR · SHIFT 2Easy

Superposition, Coherence & Intensity

The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is:

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Answer: (d)

Intensity $\propto$ slit width, so $I_1 : I_2 = 4 : 1$ and amplitudes $2 : 1$ .
$\frac{I_{max}}{I_{min}} = \left(\frac{2+1}{2-1}\right)^2 = 9$
So the answer is (d) $9 : 1$ .

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