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MHT CET 2025 (20 Apr, Shift 1) · P-V Diagrams & Cyclic Processes

P-V Diagrams & Cyclic Processes question from MHT CET 2025 (20 Apr, Shift 1)

Q22MHT CET 2025 · 20 APR · SHIFT 1Medium

P-V Diagrams & Cyclic Processes

The work done by a gas as it is taken in a cyclic process (shown in graph) is

Figure

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Answer: (d)

  1. Net work = area of triangle ABC =12(3V−V)(4P−P)=12(2V)(3P)=3PV= \frac{1}{2}(3V - V)(4P - P) = \frac{1}{2}(2V)(3P) = 3PV.
  2. A to B (rightwards), B to C (up), C to A (down-left) is anticlockwise on the P-V graph, so the work is negative.
  3. So the answer is (d) −3pv-3pv.
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