The work done in an adiabatic change in an ideal gas depends upon only: (a) change in its pressure (b) change in its temperature (c) change in its specific heat (d) change in its volume

Answer: (b). Adiabatic: Q = 0 ⇒ W = -Δ U = -nCvΔ T. Equivalently W = (nR(T₁ - T₂))/(γ - 1), which needs only Δ T. So the answer is (b) change in its temperature.

The work done in an adiabatic change in an ideal gas depends upon… | JEE Main 2025 (29 Jan, Shift 1)

Q63JEE Main 2025 · 29 JAN · SHIFT 1Easy

Thermodynamic Processes

The work done in an adiabatic change in an ideal gas depends upon only:

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Answer: (b)

Adiabatic: $Q = 0 \Rightarrow W = -\Delta U = -nC_v\Delta T$ .
Equivalently $W = \frac{nR(T_1 - T_2)}{\gamma - 1}$ , which needs only $\Delta T$ .
So the answer is (b) change in its temperature.

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