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MHT CET 2022 (11 Aug, Shift 2) · Surface Energy & Work Done

Surface Energy & Work Done question from MHT CET 2022 (11 Aug, Shift 2)

Q23MHT CET 2022 · 11 AUG · SHIFT 2Medium

Surface Energy & Work Done

The work done in blowing a soap bubble of radius $R$ is ' $W_1$ ' at room temperature. Now the soap is heated. From the heated another soap bubble of radius $2R$ is blown and the work done is ' $W_2$ '. Then

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Answer: (c)

$W = 8\pi R^2 T$ ; at the same $T$ , $W(2R) = 4W_1$ .
Heating lowers surface tension: $T' < T$ .
$W_2 = 4W_1 \dfrac{T'}{T} < 4W_1$
So the answer is (c) $W_2 < 4W_1$ .

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