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MHT CET 2024 (11 May, Shift 1) · Surface Energy & Work Done

Surface Energy & Work Done question from MHT CET 2024 (11 May, Shift 1)

Q13MHT CET 2024 · 11 MAY · SHIFT 1Medium

Surface Energy & Work Done

The work done in blowing a soap bubble of radius $R$ is $W_1$ at room temperature. Now the soap is heated. From the heated another soap bubble of radius 2 R is blown and the work done is $W_2$ . Then

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Answer: (c)

$W = 8\pi R^2 T$ ; at the same $T$ , doubling $R$ gives $4W_1$ .
Heating lowers the surface tension, $T' < T$ .
$W_2 = 8\pi (2R)^2 T' = 4W_1 \dfrac{T'}{T} < 4W_1$
So the answer is (c) $W_2 < 4W_1$ .

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