The work done in rotating a dipole placed parallel to the electric field through 180° is W. So, the work done in rotating it through 60° is (cos 0° = 1, cos 60° = 1/2, cos 180° = -1) (a) 4W (b) 3W (c) W/2 (d) W/4

Answer: (d). Wθ = pE(1 - cos θ) from the parallel position. 180°: W = 2pE; 60°: W' = pE/2 W' = W/4 So the answer is (d) W/4.

The work done in rotating a dipole placed parallel to the electric… | MHT CET 2023 (13 May, Shift 2)

Q46MHT CET 2023 · 13 MAY · SHIFT 2Medium

Electric Dipole

The work done in rotating a dipole placed parallel to the electric field through $180^\circ$ is W. So, the work done in rotating it through $60^\circ$ is $\left(\cos 0^\circ = 1,\ \cos 60^\circ = \frac{1}{2},\ \cos 180^\circ = -1\right)$

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Answer: (d)

$W_\theta = pE(1 - \cos\theta)$ from the parallel position.
$180^\circ$ : $W = 2pE$ ; $60^\circ$ : $W' = \frac{pE}{2}$
$W' = \frac{W}{4}$
So the answer is (d) $W/4$ .

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Electric Dipole question from MHT CET 2023 (13 May, Shift 2)

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