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MHT CET 2024 (9 May, Shift 2) · Splitting & Merging of Drops

Splitting & Merging of Drops question from MHT CET 2024 (9 May, Shift 2)

Q28MHT CET 2024 · 9 MAY · SHIFT 2Medium

Splitting & Merging of Drops

The work done in splitting a water drop of radius R into 64 droplets is ( $T =$ Surface tension of water)

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Answer: (b)

$64\, r^3 = R^3 \Rightarrow r = R/4$ .
Final area $= 64 \cdot 4\pi \frac{R^2}{16} = 16\pi R^2$
$W = T(16\pi R^2 - 4\pi R^2) = 12\pi T R^2$
So the answer is (b) $12\pi T R^2$ .

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