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MHT CET 2025 (26 Apr, Shift 2) · Splitting & Merging of Drops

Splitting & Merging of Drops question from MHT CET 2025 (26 Apr, Shift 2)

Q17MHT CET 2025 · 26 APR · SHIFT 2Medium

Splitting & Merging of Drops

The work done in splitting a water drop of radius R into 64 droplets is ( T=T = surface tension of water)

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Answer: (c)

  1. 64 r3=R3⇒r=R/464\, r^3 = R^3 \Rightarrow r = R/4.
  2. Final area =64⋅4πR216=16πR2= 64 \cdot 4\pi \frac{R^2}{16} = 16\pi R^2
  3. W=T(16πR2−4πR2)=12πTR2W = T(16\pi R^2 - 4\pi R^2) = 12\pi T R^2
  4. So the answer is (c) 12πTR212\pi T R^2.
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