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NEET 1995 (AIPMT) · Field of a Magnet & Magnet in a Uniform Field

Field of a Magnet & Magnet in a Uniform Field question from NEET 1995 (AIPMT)

Q33NEET 1995 · AIPMTMedium

Field of a Magnet & Magnet in a Uniform Field

The work done in turning a magnet of magnetic moment MM by an angle of 90∘90^\circ from the meridian, is nn times the corresponding work done to turn it through an angle of 60∘60^\circ. The value of nn is given by

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Answer: (c)

  1. Work from the meridian: W=MB(1−cos⁡θ)W = MB(1-\cos\theta).
  2. W90=MB(1−0)=MBW_{90} = MB(1-0) = MB, W60=MB(1−12)=MB2W_{60} = MB(1-\frac{1}{2}) = \frac{MB}{2}
  3. n=W90W60=2n = \frac{W_{90}}{W_{60}} = 2
  4. So the answer is (c) 22.
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