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NEET 2017 · Motion in a Plane (2-D Kinematics)

Motion in a Plane (2-D Kinematics) question from NEET 2017

Q14NEET 2017Easy

Motion in a Plane (2-D Kinematics)

The x and y coordinates of the particle at any time are x = 5t −- 2t2 and y = 10t respectively, where x and y are in metres and t in seconds. The acceleration of the particle at t = 2 s is

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Answer: (b)

  1. ax=d2xdt2=−4a_x = \frac{d^2x}{dt^2} = -4 m/s2^2, ay=d2ydt2=0a_y = \frac{d^2y}{dt^2} = 0
  2. Acceleration is constant, so at t=2t = 2 s it is −4-4 m/s2^2.
  3. So the answer is (b) −4-4 m s−2^{-2}.
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