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JEE Main 2025 (24 Jan, Shift 1) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from JEE Main 2025 (24 Jan, Shift 1)

Q27JEE Main 2025 · 24 JAN · SHIFT 1Medium

YDSE: Film, Medium & Two Wavelengths

The Young's double slit interference experiment is performed using light consisting of 480 nm and 600 nm wavelengths to form interference patterns. The least number of the bright fringes of 480 nm light that are required for the first coincidence with the bright fringes formed by 600 nm light is

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Answer: (c)

Coincidence: $n_1 \times 480 = n_2 \times 600 \Rightarrow \dfrac{n_1}{n_2} = \dfrac{5}{4}$ .
Least $n_1 = 5$ (coincides with 4th bright of 600 nm).
So the answer is (c) 5.

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