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NEET 2015 (AIPMT) · Young's Modulus & Elongation

Young's Modulus & Elongation question from NEET 2015 (AIPMT)

Q28NEET 2015 · AIPMTEasy

Young's Modulus & Elongation

The Young's modulus of steel is twice that of brass. Two wires of same length and of same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights added to the steel and brass wires must be in the ratio of

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Answer: (d)

  1. Lower ends at the same level means equal extensions: WsLAYs=WbLAYb\frac{W_s L}{AY_s} = \frac{W_b L}{AY_b}.
  2. Same LL and AA, so W∝YW \propto Y.
  3. WsWb=YsYb=2\frac{W_s}{W_b} = \frac{Y_s}{Y_b} = 2
  4. So the answer is (d) 2:12 : 1.
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