There are 100 divisions on the circular scale of a screw gauge of… | JEE Main 2024 (8 Apr, Shift 2)

Q27JEE Main 2024 · 8 APR · SHIFT 2Difficult

Least Count, Vernier Callipers & Screw Gauge

There are 100 divisions on the circular scale of a screw gauge of pitch $1\text{ mm}$ . With no measuring quantity in between the jaws, the zero of the circular scale lies 5 divisions below the reference line. The diameter of a wire is then measured using this screw gauge. It is found that 4 linear scale divisions are clearly visible while 60 divisions on circular scale coincide with the reference line. The diameter of the wire is:

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Answer: (c)

LC $= \dfrac{1}{100} = 0.01\text{ mm}$ ; zero 5 divisions below reference line: zero error $= +0.05\text{ mm}$
Observed reading $= 4 + 60\times 0.01 = 4.60\text{ mm}$
Diameter $= 4.60 - 0.05 = 4.55\text{ mm}$ . So the answer is (c).

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Least Count, Vernier Callipers & Screw Gauge question from JEE Main 2024 (8 Apr, Shift 2)

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