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JEE Main 2021 (27 Aug, Shift 1) · Law of Radioactive Decay

Law of Radioactive Decay question from JEE Main 2021 (27 Aug, Shift 1)

Q58JEE Main 2021 · 27 AUG · SHIFT 1Medium

Law of Radioactive Decay

There are 1010 radioactive nuclei in a given radioactive element, its half-life time is 1 minute. How many nuclei will remain after 30 seconds? (2=1.414)\left(\sqrt{2} = 1.414\right)

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Answer: (b)

  1. The question means 101010^{10} nuclei. N=N0(12)t/TN = N_0\left(\frac{1}{2}\right)^{t/T} with t/T=3060=12t/T = \frac{30}{60} = \frac{1}{2}.
  2. N=10102=10101.414≈7.07×109N = \frac{10^{10}}{\sqrt2} = \frac{10^{10}}{1.414} \approx 7.07\times10^9.
  3. So the answer is (b) 7×1097\times10^9.
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