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JEE Main 2025 (4 Apr, Shift 2) · Gas Laws & Ideal Gas Equation

Gas Laws & Ideal Gas Equation question from JEE Main 2025 (4 Apr, Shift 2)

Q30JEE Main 2025 · 4 APR · SHIFT 2Medium

Gas Laws & Ideal Gas Equation

There are two vessels filled with an ideal gas where volume of one is double the volume of other. The large vessel contains the gas at 8 kPa at 1000 K while the smaller vessel contains the gas at 7 kPa at 500 K. If the vessels are connected to each other by a thin tube allowing the gas to flow and the temperature of both vessels is maintained at 600 K, at steady state the pressure in the vessels will be (in kPa ).

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Answer: (d)

  1. Total moles are conserved: P1(2V)R⋅1000+P2VR⋅500=P(3V)R⋅600\frac{P_1(2V)}{R \cdot 1000} + \frac{P_2V}{R \cdot 500} = \frac{P(3V)}{R \cdot 600}.
  2. 8×21000+7500=3P600\frac{8 \times 2}{1000} + \frac{7}{500} = \frac{3P}{600}.
  3. 0.016+0.014=0.030=P200⇒P=60.016 + 0.014 = 0.030 = \frac{P}{200} \Rightarrow P = 6 kPa.
  4. So the answer is (d) 6.
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