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NEET 1995 (AIPMT) · Electrostatic Potential Energy

Electrostatic Potential Energy question from NEET 1995 (AIPMT)

Q66NEET 1995 · AIPMTEasy

Electrostatic Potential Energy

There is an electric field EE in xx-direction. If the work done on moving a charge of 0.2 C0.2\text{ C} through a distance of 2 m2\text{ m} along a line making an angle 60∘60^\circ with xx-axis is 4 J4\text{ J}, then what is the value of EE?

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Answer: (b)

  1. W=qEdcos⁡θW = qEd\cos\theta
  2. 4=0.2×E×2×cos⁡60∘=0.2E4 = 0.2 \times E \times 2 \times \cos 60^\circ = 0.2E
  3. E=20E = 20 N/C. So the answer is (b).
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