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NEET 2015 (AIPMT, Cancelled Paper) · Connected Bodies & Pulleys

Connected Bodies & Pulleys question from NEET 2015 (AIPMT, Cancelled Paper)

Q36NEET 2015 · AIPMT · CANCELLED PAPEREasy

Connected Bodies & Pulleys

Three blocks A, B and C, of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is

Figure

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Answer: (d)

  1. a=FmA+mB+mC=147=2 m/s2a = \dfrac{F}{m_A + m_B + m_C} = \dfrac{14}{7} = 2\text{ m/s}^2
  2. Contact force between A and B pushes B and C together: N=(2+1)×2=6 NN = (2 + 1) \times 2 = 6\text{ N}.
  3. So the answer is (d) 6 N.
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