Three bodies A, B and C have equal kinetic energies and their masses are 400 g, 1.2 kg and 1.6 kg respectively. The ratio of their linear momenta is: (a) 1: √(3): 2 (b) √(3): √(2): 1 (c) 1: √(3): √(2) (d) √(2): √(3): 1

Answer: (a). Equal KE: p ∝ √(m). pA: pB: pC = √(0.4): √(1.2): √(1.6) = √(1): √(3): √(4) = 1: √(3): 2, so the answer is (a).

Three bodies A, B and C have equal kinetic energies and their masses… | JEE Main 2024 (8 Apr, Shift 1)

Q6JEE Main 2024 · 8 APR · SHIFT 1Easy

Kinetic Energy & Momentum

Three bodies A, B and C have equal kinetic energies and their masses are $400\text{ g}, 1.2\text{ kg}$ and $1.6\text{ kg}$ respectively. The ratio of their linear momenta is:

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Answer: (a)

Equal KE: $p \propto \sqrt{m}$ .
$p_A : p_B : p_C = \sqrt{0.4} : \sqrt{1.2} : \sqrt{1.6} = \sqrt{1} : \sqrt{3} : \sqrt{4}$
$= 1 : \sqrt{3} : 2$ , so the answer is (a).

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