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JEE Main 2014 (9 Apr, Shift 1) · Combination of Capacitors

Combination of Capacitors question from JEE Main 2014 (9 Apr, Shift 1)

Q87JEE Main 2014 · 9 APR · SHIFT 1Easy

Combination of Capacitors

Three capacitances, each of 3 μ\muF, are provided. These cannot be combined to provide the resultant capacitance of:

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Answer: (d)

  1. All series: 33=1 μF\frac{3}{3} = 1\ \mu\text{F}; all parallel: 9 μF9\ \mu\text{F}.
  2. Two series + one parallel: 1.5+3=4.5 μF1.5 + 3 = 4.5\ \mu\text{F}.
  3. Two parallel + one series: 6×36+3=2 μF\frac{6\times3}{6+3} = 2\ \mu\text{F}.
  4. 6 μF6\ \mu\text{F} is not possible using all three. So the answer is (d) 6 μF6\ \mu\text{F}.
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