Combination of Capacitors question from MHT CET 2025 (26 Apr, Shift 1)

Answer: (d)

1. The lower element in parallel with $C_3$ is the battery, so $C_3$ is directly across $V$: $Q_3 = 3CV$.
2. $C_1$ and $C_2$ are in series across the same $V$: $C_s = \frac{1\cdot 2}{1+2}C = \frac{2C}{3}$, so $Q_1 = \frac{2CV}{3}$.
3. $\frac{Q_3}{Q_1} = \frac{3CV}{2CV/3} = 4.5$
4. So the answer is (d) 4.5.