Three capacitors each of capacity 4 μ F are to be connected in such a way that the effective capacitance is 6. This can be done by (a) connecting all of them in series (b) connecting them in parallel (c) connecting two in series and one in parallel (d) connecting two in parallel and one in series

Answer: (c). Two 4 in series: (4×4)/(4+4) = 2. Third 4 in parallel with this: 2 + 4 = 6. So the answer is (c) two in series and one in parallel.

Three capacitors each of capacity 4 μ F are to be connected in such a… | NEET 2003 (AIPMT)

Q93NEET 2003 · AIPMTEasy

Combination of Capacitors

Three capacitors each of capacity 4 $\mu$ F are to be connected in such a way that the effective capacitance is $6\ \mu\text{F}.$ This can be done by

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Answer: (c)