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MHT CET 2025 (22 Apr, Shift 2) · Electrostatic Potential Energy

Electrostatic Potential Energy question from MHT CET 2025 (22 Apr, Shift 2)

Q24MHT CET 2025 · 22 APR · SHIFT 2Medium

Electrostatic Potential Energy

Three charges each of magnitude $3\mu\text{C}$ , are placed on the vertices of an equilateral triangle of side 6 cm. The net potential energy of the system will be nearly $\Bigg[\frac{1}{4\pi\epsilon_0} = 9 \times 10^{9}$ SI unit $\Bigg]$

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Answer: (c)

$U = 3 \times \dfrac{kq^2}{a}$
$U = 3 \times \dfrac{9\times10^9 \times 9\times10^{-12}}{0.06} = 3 \times 1.35$
$U \approx 4.1$ J. So the answer is (c).

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