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MHT CET 2025 (25 Apr, Shift 1) · Electrostatic Potential Energy

Electrostatic Potential Energy question from MHT CET 2025 (25 Apr, Shift 1)

Q23MHT CET 2025 · 25 APR · SHIFT 1Medium

Electrostatic Potential Energy

Three charges Q,(−2q)Q, (-2q) and (−2q)(-2q) are placed at the vertices of an isosceles right angled triangle as shown in figure. The net electrostatic potential energy is zero if QQ is equal to

Figure

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Answer: (c)

  1. Q is at the right angle: legs ll, hypotenuse 2l\sqrt2 l.
  2. U=k[2Q(−2q)l+4q22l]=0U = k\left[\dfrac{2Q(-2q)}{l} + \dfrac{4q^2}{\sqrt2 l}\right] = 0
  3. 4Q=22q⇒Q=q24Q = 2\sqrt2 q \Rightarrow Q = \dfrac{q}{\sqrt2}
  4. So the answer is (c).
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