Three containers of the same volume contain three different gases. The masses of the molecules are m₁, m₂ and m₃ and the number of molecules in their respective containers are N₁, N₂ and N₃. The gas pressure in the containers are P₁, P₂ and P₃ respectively. All the gases are now mixed and put in one of these containers. The pressure P of the mixture will be (a) P (P₁ + P₂ + P₃)

Answer: (c). At the same temperature and volume, each gas exerts its own pressure in the mixture (Dalton's law). P = ((N₁ + N₂ + N₃)kT)/(V) = P₁ + P₂ + P₃ So the answer is (c) P = P₁ + P₂ + P₃.

Three containers of the same volume contain three different gases… | NEET 1991 (AIPMT)

Q45NEET 1991 · AIPMTMedium

Degrees of Freedom & Internal Energy

Three containers of the same volume contain three different gases. The masses of the molecules are $m_1, m_2$ and $m_3$ and the number of molecules in their respective containers are $N_1, N_2$ and $N_3$ . The gas pressure in the containers are $P_1, P_2$ and $P_3$ respectively. All the gases are now mixed and put in one of these containers. The pressure $P$ of the mixture will be

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Answer: (c)

At the same temperature and volume, each gas exerts its own pressure in the mixture (Dalton's law).
$P = \frac{(N_1 + N_2 + N_3)kT}{V} = P_1 + P_2 + P_3$
So the answer is (c) $P = P_1 + P_2 + P_3$ .

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