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MHT CET 2026 (20 May, Shift 1) · Electrostatic Potential Energy

Electrostatic Potential Energy question from MHT CET 2026 (20 May, Shift 1)

Q1MHT CET 2026 · 20 MAY · SHIFT 1Easy

Electrostatic Potential Energy

Three equal (+q)(+q) charges are placed in air at the vertices of equilateral triangle. If the side of equilateral triangle is ll, the net potential energy of the system is [K=14πϵ0]\left[K = \frac{1}{4\pi\epsilon_0}\right]

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Answer: (c)

  1. Three pairs, each at distance ll: U=3×kq2lU = 3 \times \dfrac{kq^2}{l}
  2. So the answer is (c) 3kq2l\dfrac{3kq^2}{l}.
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