Physics Circle home Student Login

Home›Chapters›Current Electricity PYQs›Electrical Power & Heating Effect›Question 93

NEET 1998 (AIPMT) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from NEET 1998 (AIPMT)

Q93NEET 1998 · AIPMTEasy

Electrical Power & Heating Effect

Three equal resistors connected in series across a source of emf together dissipate 1010 watt of power. What will be the power dissipated in watt if the same resistors are connected in parallel across the same source of emf?

Show answer and solution

Answer: (d)

  1. Series: Rs=3RR_s = 3R, Ps=V23R=10 WP_s = \frac{V^2}{3R} = 10\ \text{W}.
  2. Parallel: Rp=R3R_p = \frac{R}{3}, Pp=3V2R=9PsP_p = \frac{3V^2}{R} = 9 P_s.
  3. Pp=9×10=90 WP_p = 9 \times 10 = 90\ \text{W}.
  4. So the answer is (d) 90.
Report a mistake

More questions on Electrical Power & Heating Effect