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MHT CET 2026 (11 Apr, Shift 1) · Heat Conduction

Heat Conduction question from MHT CET 2026 (11 Apr, Shift 1)

Q11MHT CET 2026 · 11 APR · SHIFT 1Difficult

Heat Conduction

Three identical heat conducting rods are connected in series as shown in the figure. The rods on the side have thermal conductivity 2K2K while that in the middle has thermal conductivity KK. The left end of the combination is maintained at temperature 3T3T and the right end at TT. The rods are thermally insulated from outside. In steady state, temperature at the left junction is T1T_1 and that at the right junctions is T2T_2. The ratio T1/T2T_1/T_2 is

Figure

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Answer: (c)

  1. Resistance of a 2K2K rod =R= R, of the KK rod =2R= 2R; total =4R= 4R for a drop of 3T−T=2T3T - T = 2T.
  2. Drop per RR =2T4=T2= \dfrac{2T}{4} = \dfrac{T}{2}
  3. T1=3T−T2=5T2T_1 = 3T - \dfrac{T}{2} = \dfrac{5T}{2}, T2=T+T2=3T2T_2 = T + \dfrac{T}{2} = \dfrac{3T}{2}
  4. So the answer is (c) T1T2=53\dfrac{T_1}{T_2} = \dfrac{5}{3}.
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