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MHT CET 2019 (2 May, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2019 (2 May, Shift 2)

Q158MHT CET 2019 · 2 MAY · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

Three identical rods each of mass ' $M$ ' and length ' $L$ ' are joined to form a symbol ' $H$ . The moment of inertia of the system about one of the sides of ' $H$ ' is

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Answer: (d)

Take one vertical side of H as the axis: it gives 0.
Other vertical side is parallel at distance $L$ : $ML^2$ .
Crossbar is perpendicular with one end on the axis: $\frac{ML^2}{3}$ .
$I = ML^2 + \frac{ML^2}{3} = \frac{4ML^2}{3}$ , so the answer is (d).

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