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MHT CET 2026 (17 Apr, Shift 1) · Centre of Mass of Discrete Particles

Centre of Mass of Discrete Particles question from MHT CET 2026 (17 Apr, Shift 1)

Q2MHT CET 2026 · 17 APR · SHIFT 1Easy

Centre of Mass of Discrete Particles

Three identical spheres, each of mass 'm' kg, are kept as shown in the figure, touching each other, with their centers on a straight line. If their centers are marked as A, B, C respectively, the distance of center of mass of the system from A is

Figure

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Answer: (b)

  1. Equal masses at A, B, C on a line; take A as origin, so the positions are 00, ABAB and ACAC.
  2. xcm=m(0)+m(AB)+m(AC)3m=AB+AC3x_{cm} = \frac{m(0) + m(AB) + m(AC)}{3m} = \frac{AB + AC}{3}
  3. So the answer is (b) AB+AC3\frac{AB + AC}{3}.
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