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MHT CET 2025 (5 May, Shift 2) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2025 (5 May, Shift 2)

Q13MHT CET 2025 · 5 MAY · SHIFT 2Medium

Refraction, Glass Slab & Apparent Depth

Three immiscible transparent liquids with refractive indices $3/2, 4/3$ and $6/5$ are arranged one above the other in a container. The depths of the liquids are $3\text{ cm}, 4\text{ cm}$ and 6 cm respectively. The apparent depth of the vessel is

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Answer: (d)

Apparent depth $D = \sum \dfrac{t_k}{\mu_k}$ .
$D = \dfrac{3}{3/2} + \dfrac{4}{4/3} + \dfrac{6}{6/5} = 2 + 3 + 5$ .
$D = 10$ cm, so the answer is (d).

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