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MHT CET 2026 (13 May, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2026 (13 May, Shift 1)

Q7MHT CET 2026 · 13 MAY · SHIFT 1Medium

Refraction, Glass Slab & Apparent Depth

Three immiscible transparent liquids with refractive indices $\frac{3}{2},\ \frac{4}{3}$ and $\frac{6}{5}$ are arranged one above the other. The depths of the liquids are 3 cm, 4 cm and 6 cm respectively. The apparent depth of the vessel is

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Answer: (a)

Apparent depth of layered liquids: $D = \sum \dfrac{t_k}{\mu_k}$ .
$D = \dfrac{3}{3/2} + \dfrac{4}{4/3} + \dfrac{6}{6/5} = 2 + 3 + 5$ .
$D = 10$ cm, so the answer is (a).

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