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MHT CET 2024 (9 May, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2024 (9 May, Shift 1)

Q28MHT CET 2024 · 9 MAY · SHIFT 1Medium

Refraction, Glass Slab & Apparent Depth

Three immiscible transparent liquids with uniform refractive indices $\frac{3}{2}, \frac{4}{3}$ and $\frac{6}{5}$ are arranged one on top of another. The depths of the liquids are 3 cm 4 cm and 6 cm respectively. The apparent depth of the vessel is

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Answer: (a)

Apparent depth $D = \sum \dfrac{t_k}{\mu_k}$ .
$D = \dfrac{3}{3/2} + \dfrac{4}{4/3} + \dfrac{6}{6/5} = 2 + 3 + 5$ .
$D = 10$ cm, so the answer is (a).

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