Three liquids have same surface tension and densities ρ₁, ρ₂ and ρ₃ ( ρ₁ θ₂ > θ₃ (c) θ₁ = θ₂ = θ₃ (d) θ₁ > θ₂ < θ₃

Answer: (b). h = (2Tcos θ)/(rρ g); same h, T, r gives cos θ ∝ ρ. ρ₁ θ₂ > θ₃. So the answer is (b).

Three liquids have same surface tension and densities ρ₁, ρ₂ and ρ₃ (… | MHT CET 2026 (15 Apr, Shift 2)

Q8MHT CET 2026 · 15 APR · SHIFT 2Medium

Angle of Contact & Capillarity

Three liquids have same surface tension and densities $\rho_1, \rho_2$ and $\rho_3$ ( $\rho_1 < \rho_2 < \rho_3$ ). In three identical capillaries rise of liquid is same. The corresponding angle of contact $\theta_1, \theta_2$ and $\theta_3$ are related as

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Answer: (b)

$h = \frac{2T\cos\theta}{r\rho g}$ ; same $h$ , $T$ , $r$ gives $\cos\theta \propto \rho$ .
$\rho_1 < \rho_2 < \rho_3 \Rightarrow \cos\theta_1 < \cos\theta_2 < \cos\theta_3$ .
Cosine decreases as angle increases, so $\theta_1 > \theta_2 > \theta_3$ .
So the answer is (b).

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Angle of Contact & Capillarity question from MHT CET 2026 (15 Apr, Shift 2)

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