Physics Circle home Student Login

Home›Chapters›Surface Tension PYQs›Angle of Contact & Capillarity›Question 63

NEET 2016 (Phase 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from NEET 2016 (Phase 2)

Q63NEET 2016 · PHASE 2Medium

Angle of Contact & Capillarity

Three liquids of densities ρ\rho1, ρ\rho2 and ρ\rho3 (with ρ\rho1 > ρ\rho2 > ρ\rho3), having the same value of surface tension T, rise to the same height in three identical capillaries. The angles of contact θ\theta1, θ\theta2 and θ\theta3 obey

Show answer and solution

Answer: (b)

  1. All rise, so each θ<π2\theta < \frac{\pi}{2}.
  2. Same hh, TT, rr: cos⁡θ∝ρ\cos\theta \propto \rho; ρ1>ρ2>ρ3⇒θ1<θ2<θ3\rho_1 > \rho_2 > \rho_3 \Rightarrow \theta_1 < \theta_2 < \theta_3.
  3. So 0≤θ1<θ2<θ3<π20 \le \theta_1 < \theta_2 < \theta_3 < \frac{\pi}{2}; the answer is (b).
Report a mistake

More questions on Angle of Contact & Capillarity