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MHT CET 2024 (2 May, Shift 2) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2024 (2 May, Shift 2)

Q23MHT CET 2024 · 2 MAY · SHIFT 2Medium

Force on Current-Carrying Conductors

Three long, straight parallel wires carrying currents are arranged as shown. The wire C which carries a current of 5.0 A is so placed that it experiences no force. The distance of wire C from wire $D$ is

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Answer: (a)

C (5 A down) is antiparallel to D (15 A up) and B (10 A up), so both repel C in opposite directions.
No net force: $\frac{15}{x} = \frac{10}{15 - x}$
$225 - 15x = 10x \Rightarrow x = 9\text{ cm}$
So the answer is (a) 9 cm.

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