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NEET 2012 (AIPMT, Mains) · Centre of Mass of Discrete Particles

Centre of Mass of Discrete Particles question from NEET 2012 (AIPMT, Mains)

Q20NEET 2012 · AIPMT · MAINSEasy

Centre of Mass of Discrete Particles

Three masses are placed on the x-axis: 300 g at origin, 500 g at x = 40 cm and 400 g at x = 70cm. The distance of the centre of mass from the orgin is:

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Answer: (a)

  1. xcm=300(0)+500(40)+400(70)300+500+400x_{cm} = \frac{300(0) + 500(40) + 400(70)}{300 + 500 + 400}
  2. xcm=20000+280001200=40x_{cm} = \frac{20000 + 28000}{1200} = 40 cm
  3. So the answer is (a) 40 cm.
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