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NEET 2004 (AIPMT) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from NEET 2004 (AIPMT)

Q195NEET 2004 · AIPMTMedium

Moment of Inertia & Radius of Gyration

Three particles, each of mass m gram, are situated at the vertices of an equilateral triangle ABC of side $l$ cm (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC, in gram-cm2 units will be

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Answer: (c)

Distances from line AX: A is on it (0), B is at $l$ , C is at $\frac{l}{2}$ (C lies above the midpoint of AB).
$I = m(0) + ml^2 + m\left(\frac{l}{2}\right)^2$
$I = \frac{5}{4}ml^2$ , so the answer is (c).

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