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JEE Main 2020 (7 Jan, Shift 1) · Centre of Mass of Discrete Particles

Centre of Mass of Discrete Particles question from JEE Main 2020 (7 Jan, Shift 1)

Q17JEE Main 2020 · 7 JAN · SHIFT 1Easy

Centre of Mass of Discrete Particles

Three point particles of masses 1.0 kg, 1.5 kg and 2.5 kg are placed at three corners of a right angle triangle of sides 4.0 cm, 3.0 cm and 5.0 cm as shown in the figure. The center of mass of the system is at a point:

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Answer: (b)

Origin at the 1 kg mass: 1.5 kg at $(3, 0)$ cm and 2.5 kg at $(0, 4)$ cm.
$x_{cm} = \frac{1.5 \times 3}{5} = 0.9$ cm
$y_{cm} = \frac{2.5 \times 4}{5} = 2.0$ cm
So the answer is (b) 0.9 cm right and 2.0 cm above the 1 kg mass.

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