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MHT CET 2021 (21 Sep, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2021 (21 Sep, Shift 2)

Q126MHT CET 2021 · 21 SEP · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

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Three rings each of mass 'M' and radius 'R' are arranged as shown in the figure. The moment of inertia of system about axis YY' will be

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Answer: (b)

  1. Ring 1: YY' is a diameter, 12MR2\frac{1}{2}MR^2.
  2. Rings 2, 3: YY' is a tangent in their plane, 12MR2+MR2=32MR2\frac{1}{2}MR^2 + MR^2 = \frac{3}{2}MR^2 each.
  3. I=12MR2+3MR2=72MR2I = \frac{1}{2}MR^2 + 3MR^2 = \frac{7}{2}MR^2, so the answer is (b).
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