Physics Circle home Student Login

Home›Chapters›Centre of Mass PYQs›Composite & Cut-Out Bodies›Question 2

MHT CET 2025 (5 May, Shift 2) · Composite & Cut-Out Bodies

Composite & Cut-Out Bodies question from MHT CET 2025 (5 May, Shift 2)

Q2MHT CET 2025 · 5 MAY · SHIFT 2Medium

Composite & Cut-Out Bodies

Three rods of same mass are placed as shown in figure. The co-ordinates of centre of mass of the system are

Figure

Show answer and solution

Answer: (d)

  1. Each rod has mass mm with CM at its mid-point: (a,0)(a, 0), (0,a2)\left(0, \frac{a}{2}\right) and (a,a2)\left(a, \frac{a}{2}\right).
  2. xcm=a+0+a3=2a3x_{cm} = \frac{a + 0 + a}{3} = \frac{2a}{3}
  3. ycm=0+a2+a23=a3y_{cm} = \frac{0 + \frac{a}{2} + \frac{a}{2}}{3} = \frac{a}{3}
  4. So the answer is (d) (2a3,a3)\left(\frac{2a}{3}, \frac{a}{3}\right).
Report a mistake

More questions on Composite & Cut-Out Bodies