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MHT CET 2025 (19 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2025 (19 Apr, Shift 1)

Q88MHT CET 2025 · 19 APR · SHIFT 1Difficult

Thermodynamic Processes

Three samples X,YX, Y, and ZZ of same gas have equal volumes and temperatures. The volume of each sample is doubled, the process being isothermal for X, adiabatic for Y and isobaric for Z. If the final pressures are equal for the three samples, the ratio of the initial pressures is ( γ=3/2\gamma = 3/2)

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Answer: (b)

  1. Let the common final pressure be PfP_f and the volume double in each case.
  2. X (isothermal): PX=2PfP_X = 2P_f
  3. Y (adiabatic): PY=2γPf=23/2Pf=22PfP_Y = 2^{\gamma}P_f = 2^{3/2}P_f = 2\sqrt{2}P_f
  4. Z (isobaric): PZ=PfP_Z = P_f
  5. Ratio =2:22:1= 2 : 2\sqrt{2} : 1, so the answer is (b).
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